632=-16x^2+192x+200

Solution for 632=-16x^2+192x+200 equation:

632=-16x^2+192x+200

We move all terms to the left:

632-(-16x^2+192x+200)=0

We get rid of parentheses

16x^2-192x-200+632=0

We add all the numbers together, and all the variables

16x^2-192x+432=0

a = 16; b = -192; c = +432;
Δ = b2-4ac
Δ = -1922-4·16·432
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-192)-96}{2*16}=\frac{96}{32}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-192)+96}{2*16}=\frac{288}{32}
=9
$